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diff --git a/lib/sqlalchemy/sql/util.py b/lib/sqlalchemy/sql/util.py
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index 3077840..8719b26 100644
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--- a/lib/sqlalchemy/sql/util.py
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+++ b/lib/sqlalchemy/sql/util.py
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@@ -20,6 +20,7 @@ from .annotation import _shallow_annotate # noqa
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from .base import _from_objects
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from .base import ColumnSet
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from .ddl import sort_tables # noqa
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+from .elements import _expand_cloned
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from .elements import _find_columns # noqa
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from .elements import _label_reference
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from .elements import _textual_label_reference
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@@ -149,6 +150,16 @@ def find_left_clause_to_join_from(clauses, join_to, onclause):
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idx.append(i)
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break
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+ if len(idx) > 1:
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+ # this is the same "hide froms" logic from
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+ # Selectable._get_display_froms
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+ toremove = set(
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+ chain(*[_expand_cloned(f._hide_froms) for f in clauses])
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+ )
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+ idx = [
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+ i for i in idx if clauses[i] not in toremove
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+ ]
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+
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# onclause was given and none of them resolved, so assume
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# all indexes can match
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if not idx and onclause is not None:
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diff --git a/test/orm/test_joins.py b/test/orm/test_joins.py
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index bb9747c..4fe04f7 100644
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--- a/test/orm/test_joins.py
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+++ b/test/orm/test_joins.py
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@@ -1559,6 +1559,81 @@ class JoinTest(QueryTest, AssertsCompiledSQL):
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"ON dingalings.address_id = addresses_1.id",
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)
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+ def test_clause_present_in_froms_twice_w_onclause(self):
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+ # test [ticket:4584]
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+ Order, Address, Dingaling, User = (
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+ self.classes.Order,
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+ self.classes.Address,
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+ self.classes.Dingaling,
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+ self.classes.User,
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+ )
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+
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+ sess = create_session()
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+
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+ a1 = aliased(Address)
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+
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+ q = sess.query(Order).select_from(Order, a1, User)
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+ assert_raises_message(
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+ sa.exc.InvalidRequestError,
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+ "Can't determine which FROM clause to join from, there are "
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+ "multiple FROMS which can join to this entity. "
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+ "Try adding an explicit ON clause to help resolve the ambiguity.",
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+ q.outerjoin,
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+ a1,
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+ )
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+
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+ # the condition which occurs here is: Query._from_obj contains both
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+ # "a1" by itself as well as a join that "a1" is part of.
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+ # find_left_clause_to_join_from() needs to include removal of froms
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+ # that are in the _hide_froms of joins the same way
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+ # Selectable._get_display_froms does.
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+ q = sess.query(Order).select_from(Order, a1, User)
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+ q = q.outerjoin(a1, a1.id == Order.address_id)
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+ q = q.outerjoin(User, a1.user_id == User.id)
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+
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+ self.assert_compile(
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+ q,
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+ "SELECT orders.id AS orders_id, orders.user_id AS orders_user_id, "
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+ "orders.address_id AS orders_address_id, "
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+ "orders.description AS orders_description, "
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+ "orders.isopen AS orders_isopen "
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+ "FROM orders "
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+ "LEFT OUTER JOIN addresses AS addresses_1 "
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+ "ON addresses_1.id = orders.address_id "
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+ "LEFT OUTER JOIN users ON addresses_1.user_id = users.id",
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+ )
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+
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+ def test_clause_present_in_froms_twice_wo_onclause(self):
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+ # test [ticket:4584]
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+ Order, Address, Dingaling, User = (
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+ self.classes.Order,
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+ self.classes.Address,
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+ self.classes.Dingaling,
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+ self.classes.User,
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+ )
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+
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+ sess = create_session()
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+
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+ a1 = aliased(Address)
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+
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+ # the condition which occurs here is: Query._from_obj contains both
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+ # "a1" by itself as well as a join that "a1" is part of.
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+ # find_left_clause_to_join_from() needs to include removal of froms
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+ # that are in the _hide_froms of joins the same way
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+ # Selectable._get_display_froms does.
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+ q = sess.query(User).select_from(Dingaling, a1, User)
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+ q = q.outerjoin(a1, User.id == a1.user_id)
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+ q = q.outerjoin(Dingaling)
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+
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+ self.assert_compile(
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+ q,
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+ "SELECT users.id AS users_id, users.name AS users_name "
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+ "FROM users LEFT OUTER JOIN addresses AS addresses_1 "
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+ "ON users.id = addresses_1.user_id "
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+ "LEFT OUTER JOIN dingalings "
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+ "ON addresses_1.id = dingalings.address_id",
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+ )
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+
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def test_multiple_adaption(self):
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Item, Order, User = (
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self.classes.Item,
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