Blame SOURCES/0016-mke2fs-Document-that-too-small-blockscount-will-resu.patch

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From 7248348ed7b68e68048c3075629691745e361cad Mon Sep 17 00:00:00 2001
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From: "Richard W.M. Jones" <rjones@redhat.com>
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Date: Thu, 29 Aug 2013 13:59:14 +0100
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Subject: [PATCH] mke2fs: Document that too small blockscount will result in
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 ext2 filesystem (RHBZ#1002032).
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(cherry picked from commit 1c8986e45c3f1a7e2391bde2848667332495e3aa)
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---
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 generator/actions.ml | 10 +++++++---
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 1 file changed, 7 insertions(+), 3 deletions(-)
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diff --git a/generator/actions.ml b/generator/actions.ml
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index d679f1a..435411b 100644
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--- a/generator/actions.ml
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+++ b/generator/actions.ml
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@@ -10748,11 +10748,15 @@ or C<guestfs_rm_rf> to remove directories recursively." };
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             ["cat"; "/new"]], "new file contents"), []
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        ]);
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     shortdesc = "create an ext2/ext3/ext4 filesystem on device";
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+    (* XXX document optional args properly *)
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     longdesc = "\
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 C<mke2fs> is used to create an ext2, ext3, or ext4 filesystem
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-on C<device>.  The optional C<blockscount> is the size of the
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-filesystem in blocks.  If omitted it defaults to the size of
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-C<device>." (* XXX document optional args properly *) };
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+on C<device>.
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+
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+The optional C<blockscount> is the size of the filesystem in blocks.
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+If omitted it defaults to the size of C<device>.  Note if the
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+filesystem is too small to contain a journal, C<mke2fs> will
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+silently create an ext2 filesystem instead." };
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   { defaults with
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     name = "list_disk_labels";
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-- 
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1.8.3.1
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